Question 1119940

let b = bhim's age today.
let w = bhim's wife's age today.
let s = bhim's son's age today.
let d = bhim's daughter's age today.


the sum of their age today is 167.


b + w + s + d = 167.


b = w + 15
b = s + 35
b = d + 37


solve for w,s,d to get:


w = b - 15
s = b - 35
d = b - 37


the equation of b + w + s + d = 167 becomes:


b + b - 15 + b - 35 + b = 37 = 167


combine like terms to get:


4b - 87 = 167


add 87 to both sides of this equation to get:


4b = 254


solve for b to get b = 254 / 4 = 63.5


bhim is 63.5 today.
bhim's wife is 63.5 - 15 = 48.5 today.
bhim's son is 63.5 - 35 = 28.5 today.
bhim's daughter is 63.5 - 37 = 26.5 today.


the sum of their ages is 63.5 + 48.5 + 28.5 + 26.5 = 167.


bhim was married 5 years before his son was born.


his son was born 28.5 years ago.


add 5 to that to get bhim was married 33.5 years ago.


33.5 years ago, bhim was 63.5 - 33.5 = 30.


his wife was 48.5 - 33.5 = 15.


that's your solution.


bhim's wife was 15 when she married him.