Question 1119869
<br>
s = t^3-5t^2+5t-3<br>
v = ds/dt = 3t^2-10t+5<br>
Solve to find when v = 2:<br>
3t^2-10t+5 = 2
3t^2-10t+3 = 0
(3t-1)(t-3) = 0<br>
The velocity will be 2 when t=1/3 and when t=3.<br>
A graph of the velocity function, showing that v=2 at t=1/3 and at t=3:<br>
{{{graph(400,400,-2,4,-5,10,3x^2-10x+5,2)}}}