Question 1119882
Need help please.

I'm trying to figure out how to find three ordered pairs that satisfy the equation 4 + 2y = 3x.

I've been staring at this for a while, read, and researched, but cannot figure it out.

More than anything, I would like to understand how to get the intercepts, not just an answer.

Thank you!
<pre>4 + 2y = 3x
2y = 3x - 4 ----- Subtracting 4 from each side
{{{matrix(1,7, y, "=", (3/2)x - 4/2, "=======>", y, "=", (3/2)x - 2)}}} ------ Dividing by 2
Now, since the DENOMINATOR of the coefficient on x is 2, then the easiest and best values to substitute for x would be EVEN NUMBERS,
and better yet, 0 and other SMALL POSITIVE EVEN numbers, the likes of: 2, 4, and 6. This will give you 4 coordinates:
<b>1)</b> {{{matrix(1,7, y, "=", (3/2)(0) - 2, "=======>", y, "=", - 2)}}}
This results in coordinate point: (0, - 2). This is also the y-intercept as x = 0.

<b>2)</b> {{{matrix(1,7, y, "=", (3/2)(2) - 2, "=======>", y, "=", 1)}}}
This results in coordinate point: (2, 1). 

<b>3)</b> {{{matrix(1,7, y, "=", (3/2)(4) - 2, "=======>", y, "=", 4)}}}
This results in coordinate point: (4, 4). 

<b>4)</b> {{{matrix(1,7, y, "=", (3/2)(6) - 2, "=======>", y, "=", 7)}}}
This results in coordinate point: (6, 7). 


For the y-intercept, simply substitute 0 for x to find it. This was done above.
For the x-intercept, simply substitute 0 for y to find it, as follows:
4 + 2y = 3x
4 + 2(0) = 3x
4 = 3x
{{{matrix(1,3, 4/3, "=", x)}}}
This results in coordinate point: {{{matrix(1,4, "(", 4/3, ",", "0)")}}}.</pre>