Question 1119792
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Your method of solution is fine; and you definitely need to consider the percentage of the original solution in finding the answer.<br>
The final mixture is to be 1% SH; 1% of 8000ml is 80ml.  So you need 80ml of SH in the final mixture.<br>
If x is the number of ml of the 12% solution you use, then the amount of SH is .12x.  So you need to have<br>
{{{.12x = 80}}}
{{{x = 80/.12 = 2000/3}}} or 666 2/3 ml<br>
You want to use 666 2/3 ml of the original solution and 8000 - 666 2/3 = 7333 1/3 ml of water to get the desired mixture.<br>
And here is a common sense solution method you can use in a problem like this, whren you are diluting a given solution with pure water.<br>
The concentration of the final mixture is 1/12 that of the solution you started with.  That means 1/12 of the mixture must be what you started with, and 11/12 must be the water you added.<br>
1/12 of 8000ml = 666 2/3 ml of the original solution;
11/12 of 8000ml = 7333 1/3 ml of water