Question 1119700
April shoots an arrow upward into the air at a speed of 64 feet per second from a platform that is 34 feet high.
 The height of the arrow is given by the function h(t) = -16t^2 + 64t + 34, where t is the time is seconds.
 What is the maximum height of the arrow? 
:
The max height occurs on the axis of symmetry: Using x = -b/(2a) where
a = -16; b = 64
x = {{{(-64)/(2*-16)}}}
x = 2 seconds
Find the height at 2 sec
h(t) = -16(2^2) + 64(2) + 34
h(t) = -64 + 128 + 34
h(t) = 98 ft is max height