Question 1119675
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In all, there are 6*6 = 36 different possible outcomes (pairs of the dice values).


They all are equally probable.


Of these 36, there is only 1 (one), where the sum is less than 3.


It is the pair (1,1) with the sum of 1 + 1 = 2.


So the answer to the problem question is {{{1/36}}}.
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Solved.