Question 1119655
.
I am here to fix the errors of the @josgarithmetic solution.


<pre>
{{{4y=-x^2-8+4}}}

{{{4y=-x^2-4}}}

{{{y = -(1/4)x^2-1}}}


The parabola is downward. 


Vertex is a maximum. It is (0,-1).


FOCUS      is  (0,-2)      one unit down from the vertex
DIRECTRIX  is  y= 0.       one unit up   from the vertex
L.R.       is  4           the wide of the parabola at the focus level
</pre>