Question 1119655
{{{4y=-x^2-8+4}}}

{{{4y=-x^2-4}}}

{{{4y+4=-x^2}}}

{{{4(y+1)=-x^2}}}

{{{highlight_green(-4(y+1)=x^2)}}}


Vertex is 1 unit away from either focus or directrix.  Vertex a maximum.


VERTEX  ---
FOCUS   ---
DIRECTRIX  y=0
L.R.       4




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{{{-4(y+1)=-(x-0)^2}}}
vertex is at point(0,-1);
focus at  (0,-2), one unit downward from vertex