Question 1119647
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The key to this problem is to find the area of a general triangle when the measures of three sides are known.  Use Heron's formula:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \sqrt{p(p\,-\,a)(p\,-\,b)(p\,-\,c)}]


Where *[tex \Large a,\ b,\ &\ c] are the measures of the three sides and *[tex \Large p] is the semiperimeter:  *[tex \Large p\ =\ \frac{a\,+\,b\,+\,c}{2}]


Since you are given the ratio of the sides the actual measures of the sides can be expressed as *[tex \Large 17x,\ 10x,\ &\ 9x].


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ p\ =\ \frac{17x\ +\ 10x\ +\ 9x}{2}\ =\ 18x]


Then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \sqrt{(18x)(x)(8x)(9x)}\ =\ \sqrt{1296x^4}]


Which is given to be equal to *[tex \Large 576\text{ cm^2}]


Solve for *[tex \Large x] and then calculate *[tex \Large 17x,\ 10x,\ &\ 9x]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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