Question 1119622
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Multiply the first equation by 5; the result is equal to the second equation.<br>
Then solving the pair of equations by elimination (subtracting one equation from the other) results in the equation 0 = 0.<br>
That equation is always true; the two equations are equivalent; they are different forms of the equation for the same straight line; the system of equations is dependent.<br>
Of course, once you see that the first equation multiplied by 5 is the same as the second equation, you know that is the answer; there is no need to use elimination.<br>
Then, according to the instructions, let x = a and solve for y in terms of a:<br>
(1/2)a+y = 1/8
y = 1/8 - (1/2)a  OR  y = (1-4a)/8<br>
The solutions are any ordered pair of the form (a, (1-4a)/8).