Question 1119508
<br>
Not enough information....<br>
Let the probabilities of A, B, and C be x, y, and z, respectively.  Then<br>
x+y+z = 1  (the events are exhaustive)<br>
(1/3)z-(1/2)x = y<br>
That is two equations in three unknowns; it is impossible to find a unique solution.  There is an infinite number of solutions.