<PRE><B>Question 1119547</B>
the mother is 41 when her daughter is 9.


in how many years will the mother be three times as sold as her daughter.


let x be the number of years.


the formula is 41 + x = 3 * (9 + x).


simplify to get 41 + x = 27 + 3x


subtract 27 from both sides of the equation and subtract x from both sides of the equation to get 41 - 27 = 3x - x


simplify to get 14 = 2x


solve for x to get x = 7.


if this is correct, then 41 + 7 = 3 * (9 + 7).


simplify to get 48 = 3 * 16.


since 3 * 16 = 48, this equation is true and the solution is confirmed to be correct.


the mother is 48 in 7 years.
the daughter is 16 in 7 years.
48 is equal to 3 * 16.


the solution is 7 years.





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