Question 1119465
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Let *[tex \Large x] represent the number of men that attended.  Then the number of women that attended must be *[tex \Large 304\ -\ x].


Since *[tex \Large \frac{3}{5}] of the women left, *[tex \Large \frac{2}{5}] of the women must have remained.  Likewise, *[tex \Large \frac{4}{9}] of the men remained.


Then we are given that:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{4}{9}x\ =\ \frac{2}{5}(304\ -\ x)]


Solve for *[tex \Large x]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}

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