Question 1119464
find two numbers whose difference is 3 and whose product is 88
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Find a pair of factors of 88 that differ by 3.
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1*88 NG
2*44 NG
etc.
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If the numbers are not integers, you would have do solve a quadratic equation.
These 2 are integers, so making a quadratic,
x*(x-3) = 88 --> x^2 - 3x - 88 = 0 does not help.
At this point, to factor, you find a pair of factors of 88 that differ by 3.