Question 100974
Lets call the first number x
Now define the other numbers in terms of x
Given: one number is six less than a first number
second number = x-6
Given: a third number is twice the first number
third number = 2x
Given: the sum of the three numbers is 306
Now we can write an equation to solve for x (first number)
(first#)+(second#)+(third#) = 306
(x) + (x-6) + (2x) = 306
x + x - 6 + 2x = 306
4x - 6  = 306
4x = 312
x = 78
<b>Answer: first number is 78</b>
now we can find the other numbers
second number = x - 6
second number = 78 - 6
second number = 72
<b>Answer: second number is 72</b>
third number = 2x
third number = 2(78)
third number = 156
<b>Answer: third number is 156</b>
Check answers:
(first#)+(second#)+(third#) = 306
78 + 72 + 156 = 306
306 =306