Question 1119394
x = amount loaned at 6%.
y = amount loaned at 14%.


x + y = 20,000


.06 * x + .14 * y = 2000


these 2 equations need to be solved simultaneously.


multiply both sides of the first equation by .06 and leave the second equation as is to get:


.06x + .06y = 1200
.06x + .14y = 2000


subtract the first equation from the second to get:


.08y = 800


solve for y to get y = 800/.08 = 10,000.


that makes x = 10,000.


x + y = 20,000 so that part checks out.


.06 * 10,000 + .14 * 10,000 = 2,000 so that part checks out as well.


your solution is that 10,000 was loaned out at 6%.