Question 1119199
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The total number of ways of choosing 4 of the 30 tickets is 30 choose 4:<br>
{{{(30*29*28*27)/(4*3*2*1)}}}<br>
The number of ways of choosing both the number 1 and 2 tickets and any 2 of the other 28 tickets is (2 choose 2) times (28 choose 2):<br>
{{{1 * ((28*27)/(2*1))}}}<br>
The probability is then the ratio of those two numbers of ways:<br>
{{{((28*27)/(2*1))/((30*29*28*27)/(4*3*2*1)) = (4*3*2*1*28*27)/(30*29*28*27*2*1) = (4*3)/(30*29) = (12/870) = 2/145}}} or about 0.0138.