Question 1119314
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Distance equals rate times time, and therefore rate equals distance divided by time.  The rate of an aircraft flying into the wind is the rate of the aircraft in still air MINUS the wind speed.  The rate of an aircraft flying with the wind is the rate of the aircraft in still air PLUS the wind speed.


Distance: 8100 km, Time: 9 hours, Rate:  *[tex \Large r\ -\ r_w\ =\ 900]


Distance: 4960 km, Time: 4 hours, Rate:  *[tex \Large r\ +\ r_w\ =\ 1240]


Solve the 2X2 system for *[tex \Large r] and *[tex \Large r_w]


If you are careful with your arithmetic, you should get *[tex \Large r_w\ =\ 170 km/hr].  Since the only way to encounter wind at this sort of speed (105 miles per hour roughly) is to fly into a BIG hurricane.  Conclusion:  the pilot of your hypothetical aircraft is a suicidal (and possibly homicidal if s/he had any passengers) maniac.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}

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