Question 1119310
<font face="Times New Roman" size="+2">


Let *[tex \Large x] represent the number of hours for the 40L family.  Then the 30L family used their sprinkler for *[tex \Large 55\ -\ x] hours.  The 40L family then used *[tex \Large 40x] liters, and the other family used *[tex \Large 30(55\ -\ x)] liters.  These two amounts must sum to 2000 liters.  Hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 40x\ +\ 30(55\ -\ x)\ =\ 2000]


Solve for *[tex \Large x], then calculate *[tex \Large 55\ -\ x]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}

</font>