Question 1119237
Simplifying the exponentials gives:
{{{ e^(-a)*e^b / e^(-c) = e^(b+c-a) }}} <br> 

Then taking ln (log base e):
{{{ log(e, (e^(b+c-a))) =  b+c-a  }}} <br>

Finally, raising to the d-th power:
Ans: {{{ highlight( (b+c-a)^d ) }}}