Question 1119204
I kind of get that when you are solving an inequality like &#8739;5x+1&#8739;>3 that you are supposed to do it in two cases.  But, what I don't get is why one of those cases is 5x+1<&#8722;3 because I thought that absolute values can never be negative.  Why do we do that case?
<pre>You're correct in that absolute values can never be negative (< 0). 
However, when you do the "case" 5x + 1 < - 3, you have omitted the absolute-value bars, so you now have a regular inequality to solve.