Question 1119052
i just so happen to have the TI-84 plus so you're in luck.


the function is p(t) = 10,000 * 2 ^ .03t.


that's a strange looking formula.


are you sure it isn't p(t) = 10,000 * e ^ .03t ?????


that would make more sense.


the letter e represents the scientific constant of 2.718281828...


that formula then gives you the continuous growth rate, which is what is usually used in these type of problems.


i'll do both, just in case you really meant 2.


first i'll use the 2.


10,000 * 2 ^ .03t, when t is equal to 3, is calculated as follows in the TI-84 Plus calculator.


you enter 10000*2^(.03*3) and the calculator tells you the answer is 10643.70182 after you hit ENTER.


your entry of 10^4(2^.09) ENTER results in the same answer.


now i'll use e.


10,000 * e ^ .03t, when t is equal to 3, is calculated as follows in the TI-84 Plus calculator.


you enter 10000*2ndLN.09) and the calculator tells you the answer is 10941.74284


2ndLN gets you e^( which you then fill in with .09).


try it out and see if you get the answer you are looking for.