Question 1118964
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# of ways to get 0 face cards: choose 0 of the 12 face cards and 5 of the 40 other cards.
{{{C(12,0)*C(40,5) = 658008}}}<br>
# of ways to get 1 face card: choose 1 of the 12 face cards and 4 of the 40 other cards.
{{{C(12,1)*C(40,4) = 1096680}}}<br>
# of ways to get 2 face cards: choose 2 of the 12 face cards and 3 of the 40 other cards.
{{{C(12,2)*C(40,3) = 652080}}}<br>
The probability of getting at most 2 face cards is the total number of ways of getting at most 2 face cards, divided by the total number of ways of choosing 5 cards from the full deck of 52:<br>
{{{(658008+1096680+652080)/2598960 = 0.926}}} to 3 decimal places.