Question 1118920
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This problem, as it is formulated, allows several (more than one) different interpretations.


I will use the following one:


<pre>
    There are 22 balls in the bag, of which 10 balls are white and the rest 12 balls are black.

    The balls are undistinguished in all other aspects, excepts colors.

    The experiment consists of taking 10 balls from the bag without looking.

    Find the probability that there are at least 8 white balls among the selected 10 balls.
</pre>


<B>Solution</B>


<pre>
The probability under the question is the sum of the probabilities getting 3 independent events:


    getting 8 white @ 2 black balls  {{{C[10]^8*C[12]^2/C[22]^10}}} = {{{((10*9)/2)*((12*11)/2)*(1/646646)}}} = 0.00459293;

    getting 9 white @ 1 black balls  {{{C[10]^9*C[12]^1/C[22]^10}}} = {{{10*12*(1/646646)}}} = 0.00018557;

    getting 10 white          balls  {{{C[10]^10/C[22]^10}}} = {{{1/646646}}} = 0.00000155.


The sum of the three values is 0.00478005.


<U>Answer</U>.  The probability under the question is 0.00478005.
</pre>

Solved.


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To calculate  &nbsp;{{{C[22]^10}}}, &nbsp;&nbsp;I used this online calculator

https://www.calculatorsoup.com/calculators/discretemathematics/combinations.php