Question 1118991
{{{p=I*b^t}}}


{{{p/I=b^t}}}

{{{1/2=b^1599}}}

{{{log((1/2))=1599*log((b))}}}

{{{log((1/2))/1599=log((b))}}}

{{{log((b))=-0.0001883}}}

{{{b=0.99957}}}

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{{{10*(0.99957)^1000=highlight_green(6.5)}}}  {{{grams}}}