Question 1118932
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You must presume that the tank is absolutely full at the start of the three day period.  Also, you need to use the fact that one milliliter of water is equal to one cubic centimeter of water.


Let *[tex \Large t_e] represent the elapsed time in seconds, then  *[tex \Large t_e] is 3 days times 24 hours/day times 60 minutes per hour times 60 seconds per minute.  Step 1: Calculate *[tex \Large t_e]  (Yes, you get to do your own arithmetic throughout)


Since the water flow rate out of the tank is 10 ml/second, and it went from full to empty in *[tex \Large t_e] seconds, the volume of the tank must be *[tex \Large 10t_e].  Step 2:  Calculate *[tex \Large 10t_e] and convert from milliliters to cubic centimeters (it is one to one, so easy-peasy)


The volume of a cylinder is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ V\ =\ \pi{r^2}h].


You were given the height and now know the volume, so you must solve for the radius:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 10t_e\ =\ \pi{r^2}h]


Since the problem is asking you to find the radius to the nearest centimeter, it is necessary to convert the height in meters to height in centimeters.  There are 100 centimeters in a meter, so the height is 120 centimeters.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r\ =\ \sqrt{\frac{10t_e}{120\pi}]


Round your calculation to the nearest whole number.


The rectangular box must have a square end, the INTERNAL dimensions of which must be the diameter (two times the radius) of the cylinder, and the INTERNAL dimensions of the length must be equal to the height.  The volume of the interior of the box is the area of the square end times the length.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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