Question 1118952
let n = number of nickels.
let p = number of pennies.


the number of cents in a nickel is 5.
the number of cents in a penny is 1.
the number of cents in a dollar is 100.


your first equation is 5n + p = 920.


if you switch the number of nickels with the number of pennies, then your second equation is 5p + n = 26.80.


re-arrange the variables so that your second equation reads n + 5p = 2680.


you have 2 equations that need to be solved simultaneously.


they are:


5n + p = 920
n + 5p = 2680


multiply the second equation by -5 to get:


5n + p = 920
-5n - 25p = -13400


add the 2 equations together to get:


-24p = -12480


solve for p to get:


p = 520.


in the first original equation of 5n + p = 920, replace p with 520 to get:


5n + 520 = 920


solve for n to get:


n = (920 - 520) / 5 = 80


replace n with 80 and replace p with 520 in both original equations to get:


5n + p = 920
n + 5p = 2680


become:


5*80 + 520 = 920
80 + 5*520 = 2680.


your solution is confirmed to be good.


it is:


number of nickels is 80 and number of pennies is 520 to get a total of 920 cents which is equal to $9.20.


number of nickels is 520 and number of pennies is 80 to get a total of 2680 cents which is equal to 26.80.