Question 100392
2(y+2)+y = 19-(2y+3)
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Multiply what's inside the brackets, think of -1 being outside the (2y+3)you have:
2y + 4 + y = 19 - 2y - 3)
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Combine like terms on both sides:
3y + 4 = 16 - 2y
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We want to perform algebra operations to isolate y on the left and numbers on the right.
Add 2y to both sides and you have:
3y + 2y + 4 = 16
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Add the y's  and subtract 4 from both sides:
5y = 16 - 4
:
5y = 12
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Divide both sides by 5 and you have;
y = 12/5
:
y = 2.4
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Check your solution by substituting 2.4 for y, in the original equation:
Step-by-step
2(y+2)+y = 19-(2y+3) 
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2(2.4 + 2)+ 2.4 = 19-(2(2.4)+ 3)
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2(4.4) + 2.4 = 19 - (4.8 + 3)
:
8.8 + 2.4 = 19 - 7.8
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11.2 = 11.2; equality reigns, our solution is correct
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Can you understand this now? Any questions?