Question 1118893
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It could be anything I would like it to be until you provide a definition of the function *[tex \Large f].


But once you have defined *[tex \Large f], then you can calculate the value *[tex \Large f(2)].  Then you plug that value into *[tex \Large h] and calculate the result.


For example, let's say that *[tex \Large \phi(x)\ =\ x^2\ +\ 2x\ -\ 5] and *[tex \Large \psi(x)\ =\ x\ -\ 3].  And let's say that we want to know the value of *[tex \Large \phi\(\psi(5)\)]


First, calculate *[tex \Large \psi(5)].  *[tex \Large \psi(5)\ =\ 5\ -\ 3\ =\ 2].  Then calculate *[tex \Large \phi(2)\ =\ (2)^2\ +\ 2(2)\ -\ 5\ =\ 3].


You could also define *[tex \Large \phi\(\psi(x)\)] in general by


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \phi\(\psi(x)\)\ =\ (x\ -\ 3)^2\ +\ 2(x\ -\ 3)\ -\ 5]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ =\ (x^2\ -\ 6x\ +\ 9)\ +\ 2x\ -\ 6\ -\ 5]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ =\ x^2\ -\ 4x\ -2]


Then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \phi\(\psi(5)\)\ =\ (5)^2\ -\ 4(5)\ -\ 2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ = 25\ -\ 20\ -\ 2\ =\ 3]


As we would expect given our earlier result.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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