Question 1118882
There are 13 clubs and 4 jacks.   If we say there are 3 jacks that are not clubs then there are 13+3 = 16 cards that meet the requirement,  and the probability of selecting one of them is  16/52 = {{{ highlight( 4/13 )}}}

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As an alternative approach,  apply  P(A u B) = P(A) + P(B) - P(A ∩ B)  

P(club) = 13/52
P(jack) = 4/52  and 
P(jack  ∩ club) = 1/52

   P(jack or club) = {{{13/52 + 4/52 - 1/52 = 16/52 = highlight( 4/13 )  }}}