Question 1118811
 I have a bucket that is 90" across the top and 24" across the bottom.
 Height from top to bottom is 36 inches.
 What is the slope of each side ?
R = large radius = 45"
r = small radius = 12"
:
This is a frustrum of a cone which we have some formulas, one of which is: 
s = {{{sqrt(a^2+h^2)}}} where
s = slope
a = difference between radii, 45-12 = 33"
h = height of the bucket, 36"
s = {{{sqrt(33^2 + 36^2)}}}
s = {{{sqrt(1089+1296)}}}
s = {{{sqrt(2385)}}}
s = 48.84" is the slope
:
 What does the slope become if all measurements remain the same except the bottom is 30" instead of 24"?
If the bottom is 30, the small radius = 15", therefore
a = 45-15 = 30
s = {{{sqrt(30^2 + 36^2)}}}
s = {{{sqrt(900+1296)}}}
s = 46.86" is the slope
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