Question 1118755
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Let *[tex \Large x] represent the amount invested at 5%.  Then the amount invested at *[tex \Large 2%] must be *[tex \Large $5600\ -\ x].


The amount earned on *[tex \Large x] dollars for a year invested at 5% is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.05x]


The amount earned on *[tex \Large 5600\ -\ x] dollars for a year invested at 2% is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.02(5600\ -\ x)]


We are given that these two amounts are equal, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.05x\ =\ 0.02(5600\ -\ x)]


Solve for *[tex \Large x], then calculate *[tex \Large 5600\ -\ x]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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