Question 1118752
.
 In the quadratic equation
x^2 + mx + 2=0, the roots are
consecutive. Find the values of m .
~~~~~~~~~~~~~~~~~


Your formulation is <U>fatally uncompleted</U>. &nbsp;The correct and the complete formulation is &nbsp;<U>THIS</U>:


<pre>
    In the quadratic equation  x^2 + mx + 2=0,  the roots are consecutive <U>integer numbers</U>. Find the values of m .
</pre>

<U>Solution</U>


<pre>
From Vieta's theorem, the constant term "2" is the product of the roots that are two consecutive integer numbers.


Hence,  the roots are  EITHER  1 and 2  with m equal to -(1+2) = -3

                       OR     -2  and -1  with m equal to -((-1) + (-2)) = 3.


<U>Answer</U>.  The problem has two solutions:  a)  the roots 1 and 2 with m = -3,  and

                                         b)  the roots are -2 and -1 with m= 3.
</pre>

Solved.


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The solution by &nbsp;@josgarithmetic &nbsp;was uncompleted.


What he presents as a solution, &nbsp;is not a solution at all.


It is a RUBBISH.  &nbsp;Simply ignore it for your safety. &nbsp;It makes no sense.


Avoid his writing and his "solutions" as much as you can.



You will learn NOTHING from him.