Question 1118719
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(x-4)²+8=0
(x+2)²=3(x+2)
(2x-1)²=(x+1)²
2x(x+4)=(x-3)(x-3)
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Those appear to be four separate equations.



{{{(2x-1)^2=(x+1)^2}}}
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{{{sqrt((2x-1)^2)=sqrt((x+1)^2)}}}
{{{2x-1=0+- (x+1)}}}
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EITHER
{{{2x-1=-x-1}}}
{{{3x=0}}}
{{{x=0}}}
OR
{{{2x-1=x+1}}}
{{{x-1=1}}}
{{{x=2}}}
-
result:  {{{system(x=0,OR,x=2)}}}


Be sure to check if they both work.


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{{{(x+2)^2=3(x+2)}}}
Simplify the equation first, and then solve.  Start THIS WAY:
{{{(x+2)^2-3(x+2)=0}}}
{{{(x+2)(x+2-3)=0}}}, and then continue...
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{{{2x(x+4)=(x-3)(x-3)}}}
Simplify first, and then solve...
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