Question 1118671
3 sin(theta) = 2 cos(theta)

9sin^2 theta = 4 cos^2 theta
9sin^2 theta = 4(1 - sin^2 theta)
13 sin^2 theta = 4
sin theta = 2/sqrt(13)

sin theta = 4 cos theta
sin^2 theta = 16 cos^2 theta
sin^2 theta = 16 - 16 sin^2 theta
17 sin^2 theta = 16

sin theta = 4/sqrt(17)