Question 1118548
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The question doesn't really make any sense.  The probability that the first card is a face card is not affected by what card is drawn second.<br>
The solution by the other tutor actually shows this; but it is hard to see because of the way he shows his calculations, and by the fact that his final answer in fraction form is not in simplest form.<br>
Let A represent drawing a face card on the first draw and B represent drawing an 8 on the second.  Then<br>
P(A) = 12/52 = 3/13
P(B) = 4/51<br>
Then the conditional probability is<br>
P(A|B) = (P(A and B)/P(B)) = (P(A)*P(B))/P(B) = P(A) = 3/13