Question 1118548
let event A be the probability of first drawing a face card = 12/52 = 3/13
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let B be the probability of second drawing an 8 = 4/51(because the face card was drawn first)
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Probability (P) (A|B) = P (A intersection B) / P(B)
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P (A intersection B) means P that both events happen, therefore
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P (A intersection B) = (3/13) * (4/51) = 12/663 = 4/221
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P (A|B) = (4/221) / (4/51) = 51/221 is approximately 0.231
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