Question 1118530
<br>
60% = 3/5; so A owned 3/5 of the buses and B owned 2/5.<br>
Let the number owned by A be 3x and the number owned by B be 2x; the total number of buses is 5x.<br>
When B adds 80 buses, it now has (2x+80) buses, which is 52% of the total, and the total number of buses is now 5x+80:<br>
{{{(2x+80)/(5x+80) = 0.52 = 13/25}}}
{{{25(2x+80) = 13(5x+80)}}}
{{{50x+2000 = 65x+1040}}}
{{{15x = 960}}}
{{{x = 64}}}<br>
Originally the number of buses A had was 3x = 3*64 = 192, and the number B had was 2x = 2*64 = 128; the total number of buses was 5x = 320.<br>
After adding 80 new buses, the number B has is 208.<br>
CHECK: B now has 208 buses, and the total number is 192+208 = 400.  208/400 = 52/100 = 52%.