Question 100782
{{{ 4x^2-8x+3=5 }}} 


This can be written as: 



{{{ 4x^2 - 8x + 3 - 5 = 0 }}} 


{{{4x^2 - 8x - 2 = 0 }}} 


To find the roots factor out the above polynomial using the formula method. 


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 


Here in the above polynomial a = 4, b = -8 and c = -2



{{{x = (8 +- sqrt( 64 + 32 ))/(8) }}} 



{{{x = (8 +- sqrt(96))/8 }}}



Taking 8 out as a common factor we get:


{{{x = (1 +- sqrt(12)) }}}



{{{x = 1 + - 2 sqrt(3) }}} 



thus, the solution.