Question 1118375
{{{a<0}}} and you can begin with   {{{y=a(x+3)^2+35}}}.


Solve for a, and substitute the other given point.
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{{{a(x+3)^2=y-35}}}

{{{a=(y-35)/(x+3)^2}}}

{{{a=(23-35)/(-5+3)^2}}}

{{{a=(-12)/(-2)^2}}}

{{{a=-3}}}
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{{{highlight(y=-3(x+3)^2+35)}}}