Question 1118336
Angle {{{theta}}}; not angle {{{0}}}.


I will do this for only two of the trigonometric ratios; you can do the others according to their definitions.


{{{sin(theta)=BC/AC=24/26=12/13}}}
{{{highlight(sin(theta)=12/13)}}}


The Pythagorean Theorem relationship will allow for cosine.

{{{cos^2(theta)=1-sin^2(theta)}}}

{{{cos(theta)=sqrt(1-(12/13)^2)}}}

{{{cos(theta)=sqrt(13^2/13^2-12^2/13^2)}}}

{{{cos(theta)=((169-144)/13^2)}}}

{{{cos(theta)=sqrt((25/13)^2)}}}

{{{highlight(cos(theta)=5/13)}}}