Question 1118274
The 1st card is guaranteed to be one of
the 4 suits and you don't care which suit
it is, so the probability is {{{ 1}}}
---------------------------------------
There are now {{{ 51 }}} cards left. There are
{{{ 52 - 13 = 39 }}} cards of other suits, so the P
of getting a different suit is: {{{ 39/51 }}}
---------------------------------------
Now there are {{{ 50 }}} cards left, and 2 of the
suits have been eliminated. There are
{{{ 52 - 26 = 26 }}} cards to choose from, so
the P of getting a different suit is:
{{{ 26/50 }}}
----------------------------------
P( 3 different suits ) = {{{ 1*(39/51)*(26/50) }}}
{{{ ( 39*26 ) / ( 51*50 ) }}}
{{{ 1014 / 2550 = .39765 }}}
-----------------------------
Get another opinion also  if you choose