<PRE><B>Question 1118232</B>
``West of Albuquerque, New Mexico, Route 40 eastbound is straight and makes a steep descent towards the city, The highway has a 6% grade which means that its slope is -6/100. Driving on this road you notice from elevation signs that you have descended a distance of 1000 ft. What is the change in our horizontal distance?&#39;&#39;.

(When I graphed this I got a approx answer in the range of 1660) 
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tan(6) = v/h
v = 1000
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h = 1000/tan(6)
h =~ 9514 feet
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