Question 1118158
.
A bag contains 10 red, 8 green and 7 blue balls, If two balls are picked at random one after the other 
without replacement from the bag, what is the probability that: 



(i) they are of the different colors


<pre>

     The favorable sets are  (R,G) or (R,B) or (G,B).


     Correspondingly, the probability under the question is


        P = {{{(10/25)*(8/24)}}} + {{{(10/25)*(7/24)}}} + {{{(8/25)*(7/24)}}}.


        Here 25 = 10 + 8 + 7 is the total number of balls and 24 = 25-1.


     You may complete it as a fraction or use your calculator to get the decimal number.
</pre>


(ii) at least {{{highlight(cross(a))}}} <U>one</U> ball is blue?


<pre>
     The favorable sets are  (R,B) or (G,B) or (B,B).


     Correspondingly, the probability under the question is


        P = {{{(10/25)*(7/24)}}} + {{{(8/25)*(7/24)}}} + {{{(7/25)*(6/24)}}}.


     You may complete it as a fraction or use your calculator to get the decimal number.
</pre>