Question 1118207
<br>
{{{9^x = (3^2)^x = 3^(2x)}}}, so {{{log(9,5)=x}}} --> {{{log(3,5)=2x}}}<br>
{{{27^y = (3^3)^y = 3^(3y)}}}, so {{{log(27,2)=y}}} --> {{{log(3,2) = 3y}}}<br>
Then<br>
{{{log(3,100) = log(3,((2^2)*(5^2))) = 2*log(3,2)+2*log(3,5) = 2(3y)+2(2x) = 4x+6y}}}