Question 1118078
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There is a 50% probability of a head on the first toss and a 50% probability of getting head on the second toss.  So there is a 0.5 X 0.5 = 0.25 = 25% probability of getting two heads.


Same thing for getting two tails.


50% to get a head first and then 50% to get a tail, so P(TH) = 25%


50% to get a tail first and then 50% to get a head, so P(HT) = 25%


Hence, 50% probability of getting a head and a tail in either order.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ E(x)\ =\ (0.25\cdot 0.68)\ +\ (0.5\cdot 0.34)\ -\ (0.25\cdot 1.02)]


You can do your own arithmetic. 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
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