Question 1118044
{{{3B=(matrix(2,2,
12,3,0,6))}}}
{{{2A=(matrix(2,2,
3,6,9,15))}}}
So then,
{{{3Bx2A=(matrix(2,2,
(12*2+3*6),(12*4+3*10),(0*2+6*6),(0*4+6*10)))}}}
.
.
{{{3Bx2A=(matrix(2,2,
(24+18),(48+30),36,60))}}}
.
.
{{{3Bx2A=(matrix(2,2,
42,78,36,60))}}}