Question 1117918
{{{(2x-1)x=66}}}  for length 2x-1 and with x.


{{{2x^2-x-66=0}}}


{{{x=(1+-sqrt(1+4*2*66))/4}}}

{{{x=(1+sqrt(1+8*66))/4}}}

{{{x=(1+sqrt(529))/4}}}

{{{x=(1+23)/4}}}

{{{highlight(x=6)}}}--------width

{{{highlight(11)}}}-------length



You could also find the same result by factoring.