Question 1117857
{{{8=2.05(1.8)^t}}}


{{{1.8^t=8/2.05}}}


{{{1.8^t=3.90243}}}


{{{t*log((1.8))=log((3.90243))}}}


{{{t=log((3.90243))/log((1.8))}}}


{{{t=2.316}}}
This would be between or in years 2004


----


{{{1.8^t=2}}}

{{{t*log((1.8))=log((2))}}}

{{{t=log((2))/log((1.8))}}}