Question 1117829
POSITIVE integers, n-1, n, n+1 



{{{(n-1)(n+1)n=8(n-1+n+n+1)}}}
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{{{n(n^2-1)=8(3n)}}}
{{{n^3-n=24n}}}
{{{n^3-25n=0}}}
{{{n(n^2-25)=0}}}


n=0 will not work according to the description.
{{{highlight_green(n=5)}}}


Sum Of Their Squares:
{{{4^2+5^2+6^2}}}
{{{16+25+36}}}
{{{highlight(77)}}}